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    Decimal resistance box production ----- Resistance Box

     

    Author: Liu Deyou The circuit diagram of the circuit shown in the drawings is a double-knife ten-throw switch. Only the resistance series of (I), (II) and (VIII) three units is shown, and the other five units of the resistance series are not drawn (only the resistance value is different). The resistance box is only 4 resistors per unit circuit, and eight units use 32 resistors. The resistance of any resistance between 0 Ω to 10 mΩ can be obtained by the tool of the eight double-knife cutting switch. Now use only (i) unit circuit as an example, as an example. To make it easy, the line is called the bus connected to the A point, and the line is called the line with the (II) unit. When K1 is transferred to the knife position 4 (X0.1Ω) point, the resistance R = R2 + R4 = 0.2 Ω + 0.2 Ω = 0.4 Ω between the upper and lower bbs. This is consistent with the gear display 4 (X0.1Ω). When KL throws 0 bits. The value is OΩ: It is not difficult to see that when K1 is set, the resistance value is 0.9Ω, which is not difficult to see from the (i) unit circuit analysis, when the eight range switches are 9 (highest gear), the A, B end The resistance value is a total resistance value of 32 resistors 10MΩ, and the additional resistance of the line distribution is not considered. Its theoretical resistance should be (10mΩ ~ 0.1 Ω). After the resistance box is made, it can be used in circuit debugging, experiment, or maintenance. For example, if a 2.058mΩ resistor is required, the dial switch KBP8, KBP7 ... KBPL is allocated to 2, 0, 5, 8, 0, 0, 0, 0, at this time, can be in A, B. End the 2.058 mF / resistance value. Figure 1 circuit dials K8 ... K1. Note: No resistance value must be allocated to the "0" bit. And each resistance value must have "eight".

     

     

     

     

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