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    Description of the logical operation method of single-chip accumulator A

     

    The logic operation of the accumulator A for the microcontroller: CLR A; 0. The value of the value is 0, the single-cycle single-byte instruction is the same as the MOV A, and the effect. CPL A; reflect the value in A RL A; logic to the value of A RLC A; Logic left by plusing the value in A RR A; logically right of the value in A RRC A; Logic movement to the value of the value plus the value Swap A; high value, low value, low 4 digits. Example: (a) = 73h, execute CPL A, this: 73H is chemical as 01110011, It is a 10001100 in opposing position, which is 8CH. RL A is sent to the value of the value in (a) to 0th, and the 0th is 1 bit, and push it according to the class. Example: The value in A is 68h, executes RL A. 68H is chemically binary 01101000, moving by the above figure. 01101000 is 11010000, that is, D0H. RLC A is shifted by the inlet bits (c) on (a). Example: The value of the value is 68h, and the value is 1, then execute RLC A After 1 01101000, the result is 0 11010001, that is, the value of the C-entertel bit becomes 0, and (a) becomes D1H. RR A and RRC A don't talk more, please refer to the two routines above. SWAP A is exchanged for high, low 4 digits in A. Example: (a) = 39h, after SWAP A, the value in A is 93h. How is it just right? Because this is a 16-based number, each 16-in number represents 4 bits. Note that if this is: (a) = 39, there is no H, after SWAP A, may not be (a) = 93. To make it a binary and then calculated: 39 is a binary 10111, that is, 0001, 0111 high 4 bits are 0001, low 4 bits are 0111, and the exchange is 0110001 after exchange, that is, 71h, ie 113. Exercise, known (a) = 39h, perform the results of each step after performing the following single-chip command CPL a RL A CLR C RRC A Setb C RLC A Swap A, Read more

     

     

     

     

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