ANL A, RN; A and Rn in RN, and ', the result is sent to A
ANL A, Direct; A and Direct in Direct Bit 'and', the result is sent to A
ANL A, @ ri; A and the value of the value in the site addressing unit @RI, and the result is sent to A
ANL A, # data; a with immediate DATA bit 'and', the result is sent to A
ANL DIRECT, A; Direct Medium Value and Value Bit in A and ', the result is sent to Direct
ANL DIRECT, # DATA; DIRECT in Direct The number of times DATA bit 'and', and the result is sent to Direct.
The key to these instructions is to know what is logical. The logic here is a bit bit and
Example: 71h and 56h faults will write two numbers into binary form:
(71h) 01110001
(56h) 00100110
The result 00100000 is 20h, from the above formula, the value of the two participating calculations is 0, and the result is 0, two of the same one, the result is 1.
Understand the logic and calculation rules, and the results will naturally come out. Note from each instruction
Let's take some routines below.
Mov A, # 45h; (a) = 45H
MOV R1, # 25h; (r1) = 25h
MOV 25h, # 79h; (25h) = 79h
ANL A, @ R1; 45H and 79H standby, the result is sent to 41h (a) = 41h
ANL 25H, # 15H; 25H (79H) and 15H phase with the result (25h) = 11h)
The value (11h) in ANL 25H, A; 25H is in the value (41h) of A, the result is (25h) = 11h
After knowing the functionality of logic and instructions, logic or logical varying or function is very simple. Logic or bit "or", that is, "1" is 1, "0" is 0. example:
10011000
Or 01100001
Result 11111001
It is the same "different or", the same "0", which is "1". example:
10011000
Different or 01100001
Result 11111001
And all or instructions are to replace ANL in the referral to orl, while the different or instructions are replaced with an XRL. which is
Or instructions:
ORL A, RN; A and RN value bit 'or', the result is sent to A
Orl A, Direct; A and Value Bits 'or' in the address addressing unit @RI, the result is sent to A
Orl A, # data; A and stand in Direct Run "or ', the result is sent to A
Orl A, @ ri; A and ie Data Bit 'or', the result is sent to A
Orl Direct, A; Direct Medium Value and Value Bit 'or' in A. The result is sent to Direct
ORL DIRECT, # data; Direct's value and immediate DATA bit "or ', the result is sent to Direct.
Different or directive:
XRL A, RN; A and RN in the RN value ', the result is sent to A
XRL A, Direct; A and Direct's Value Bits 'Differences or', and the result is sent to A
XRL A, @ ri; A and the value of the value in the site @RI, the result is sent to A
XRL A, # data; a and immediate DATA bit by or ', the result is sent to A
XRL Direct, A; Direct Medium Value and the value of the value in A. The result is sent to Direct
XRL Direct, # data; value in Direct and immediate DATA bit bit 'is or', and the result is sent to Direct.
Exercise:
Mov A, # 24h
MOV R0, # 37h
Orl A, R0
XRL a, # 29h
Mov 35h, # 10h
ORL 35h, # 29h
MOV R0, # 35h
ANL A, @ r0
Fourth, control the transfer class instruction
Conditional transfer class instruction
Short transfer class instruction
AJMP Addr11
Long transfer class directive
LJMP Addr16
Relative transfer instruction
SJMP REL
Three instructions above, if you want to analyze it carefully, differences, but when you start learning, you can ignore so much, all understand: JMP markings, that is, jump to a label. In fact, the LJMP label, we have already contacted in the previous routines, and know how to use it. The same is true of AJMP and SJMP. So what is their difference? Different in the range of jumps. It's so far away, and LJMP can jump 64K so far (of course, it is nothing to do). And AJMP can only jump 2k distance, while SJMP can only jump 256 so far. In principle, all places where SJMP or AJMP can be replaced with LJMP. Therefore, when you start learning, you can use LJMP when you need to jump, except for an occasion. What are the occasion? First understand the AJMP, AJMP is a double-byte directive, but also say that this instruction itself takes up two units of the memory (ROM). LJMP is three-byte instructions, ie three units of the memory (ROM). Below is the fourth jump instruction.
Indirect transfer instruction
JMP @ A + DPTR
The purpose of this instruction is also jumping, where is it going? This can not be simply determined by the label. Let us start from an actual routine.
MOV DPTR, # Tab; send the address represented by Tab into DPTR
Mov A, R0; Number of Number of R0 (see below)
Mov B, # 2
MUL A, B; A value in A by 2 (see below)
JMP A, @ A + DPTR; jump
Tab: AJMP S1; Jump Form
AJMP S2
AJMP S3
figure 2
image 3
Application Background: In the microcontroller development, the keyboard is often used, see the keyboard of the 9 buttons above. Our requirements are: When you press the function key A ........G to complete the different features. This is expressed by the language design language, that is: pressing a different key to perform a different block to complete the different functions. How is it realized?
Looking at Figure 2, the previous program is read into the value of the button. If the key value obtained after pressing the 'A' button is 0, the value obtained after pressing the 'b' button is '1', and then according to not The same value is jump, and if the key value is 0, it is transformed to S1, and 1 is transferred to S2 execution. . . . How to achieve this feature? Read more
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